The radii of second orbit of he+ is
Webb13 juni 2024 · The radii are in the ratio 6:3:2. Explanation: The radii of the first orbits of a hydrogen-like ion are given by the equation r = ħ2 Zmekee2 Since everything except Z is constant, we can rewrite the formula as r = k Z Then the ratios of the three radii for Z = 1,2 and 3 are r1:r2:r3 = 1 1: 1 2: 1 3 = 6:3:2 Answer link WebbL is defined to be r x p, which is r*p*sin (theta), where theta is the angle between the radius vector and the momentum vector. Since they are moving in a circle, that means that p …
The radii of second orbit of he+ is
Did you know?
Webb4) Calculate the radius of 2nd orbit in He +. 5) The radius of which of the following orbit is same as that of first orbit of hydrogen atom.... A) second orbit of He + B) first orbit of Li … WebbThe maximum and minimum speeds of a comet that orbits the Sun are 80 and 10 km/s respectively. The ratio of the aphelion distance of the comet to the radius of the Earths orbit is _____.(Assume that Earth moves in a circular orbit of radius 1.5 108 km with a speed of 30 km/s.)
Webb20 juli 2024 · asked Jul 20, 2024 in Chemistry by PrernaChauhan (46.8k points) closed Jul 21, 2024 by PrernaChauhan If radius of second Bohr orbit of the He+ ion is105.8 pm, … http://www.adichemistry.com/jee/qb/atomic-structure/1/q2.html
WebbSolution The correct option is B 9: 32 As per Bohr's theory, T n ∝ n3 Z2 where, T n = Time period of revolution n = orbit number and Z = atomic number of element For He+, Z = 2, n =2 T He+ = K× 23 22 where, K is the proportionality constant Similarly, for Li2+, Z =3, n= 4 T Li2+ = K× 43 32 Taking the ratio of time period of He+ and Li2+, WebbPractice Test 22 : Dual Nature of Radiation and Matter. 1. A particle of mass 1 mg has the same wavelength as an 8. Which of the following when falls on a metal will emit electron moving with a velocity of 3×106 ms–1. The velocity photoelectrons ? of the particle is: (a) UV radiations (b) Infrared radiation (a) 2.7× 10–18 ms–1 (b) 9 × 10–2 ms–1 (c) Radio …
WebbIf radius of second orbit of He+ is x nm then the (1) SF4 (2) ClF3 radius of the first orbit of Li2+ will be (3) NH3 (4) PCl3 x
WebbThe ratio of radius of 2 nd and 3 rd Bohr's orbit is: A 3 : 2 B 9 : 4 C 2 : 3 D 4 : 9 Medium Solution Verified by Toppr Correct option is D) We know that the radius of an orbit in a … can prezzy cards be used overseasWebb28 juni 2024 · answered ASSERTION - The radius of second orbit he He+ is equal to that of first orbit of hydrogen. REASON- The radius of an orbit in hydrogen like species is directly propotional to Z and inversely propotional to n. * Both the Assertion and the Reason are correct and the Reason is the correct explanation of the Assertion. flamingo feather coatWebbThe correct option is A 6: 4:3Bohr's radius for nth orbit, rn = 0.529[ n2 Z] ∘Awhere n=Energy level, Z =Atomic numberFor He+ ion: n =1, Z =2rHe+ =0.529[12 2] ∘AFor Li2+ ion: n= 1, Z … flamingo feather plantWebb6 apr. 2024 · For He+ ion, n = 2 for the second orbit, and the atomic number is 2. Substituting the values in the formula, we get r = n 2 Z × 0.529 A o ⇒ r = ( 2) 2 2 × 0.529 A … flamingo feather razorWebb2 jan. 2024 · The energy of the second Bohr orbit in the hydrogen atom is - 3.41 eV. The energy of the third Bohr orbit of He+ ion would be (a) - 13.62 eV (b) - 1.70 eV (c) - 6.06 eV (d) - 0.85 eV Please log in or register to answer this question. 1 Answer 0 votes answered Jan 2, 2024 by Vikash Kumar (261k points) (c) - 6.06 eV Explanation: can prf inhibit the cell migrationWebbSince negative of Ionization energy is the energy of first stationary state, for He+, the energy of 1st level is -19.6 x 10^-18 J atom-1. The energy of an electron in 1st level for He+can be written as: E1 = -K (Z^2 /n^2 ) = - K x (2^2/1^2 ) = -4K Hence K = -19.6 x 10^-18 / 4 = 4.9 x 10^-18 J atom-1 can price to book value be negativeWebbSolution: Let us consider the nth bohr orbit, rn = 4π2mZe2n2h2 For hydrogen atom z = 1, first orbit n = 1 r1 = 4πr2me2h2 = 0.592A0 (i)For H e+ ion, Z = 2, third orbit, n = 3 r3(H e+) = 4π2m×2×e232h2 = 29 [4π2me2h2] = 29 × 0.592 = 2.380A0 (ii) For Li2+ ion, Z = 3, second orbit n = 2 r2 (Li2+) = 4π2m×3×e222h2 = 34 [4π2me2h2]= 0.705A0 can pride be a theme